This tutorial shows how we can use C# to generate a random password. VB version.
Generating random passwords can increase the security of a website by taking the process out of the hands of the user, or simply providing an alternative, and thus reducing the chance of easily-guessable passwords being used. This tutorial shows a simple method of creating a random password.
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First, we create the ASPX page:| <form id="form1" runat="server"> <div> Enter Required Password Length: </div><asp:TextBox ID="TextBox1" runat="server" Columns="2" MaxLength="2"></asp:TextBox><br /> <asp:Label ID="Label1" runat="server"></asp:Label><br /> <asp:Button ID="Button1" runat="server" Text="Generate Password" OnClick="Button1_Click" /> </form> |
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The simple method is shown below. This is how the code-behind should look:
| Imports Microsoft.VisualBasic Imports System Imports System.Data Imports System.Configuration Imports System.Web Imports System.Web.Security Imports System.Web.UI Imports System.Web.UI.WebControls Imports System.Web.UI.WebControls.WebParts Imports System.Web.UI.HtmlControls Partial Public Class _Default Inherits System.Web.UI.Page End Class Protected Sub Page_Load(ByVal sender As Object, ByVal e As EventArgs) If IsPostBack Then End SubLabel1.Text = "Please enter a password length (e.g. 8)" End IfPublic Shared Function CreateRandomPassword(ByVal PasswordLength As Integer) As String Dim _allowedChars As String = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789" End FunctionDim randNum As New Random() Dim chars(PasswordLength - 1) As Char Dim allowedCharCount As Integer = _allowedChars.Length For i As Integer = 0 To PasswordLength - 1 chars(i) = _allowedChars.Chars(CInt(Fix((_allowedChars.Length) * randNum.NextDouble()))) Next iReturn New String(chars) Protected Sub Button1_Click(ByVal sender As Object, ByVal e As EventArgs) If TextBox1.Text <> "" Then End SubDim myInt As String = TextBox1.Text.ToString() End IfLabel1.Text = "Your generated password is: " & CreateRandomPassword(Integer.Parse(myInt)) |
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